What's the best way for forcing sharing between 2 series capacitors rather than add resistor in parallel with the capacitor. Another question if you have output of the power supply for example 10vdc and 1 a dc and switching frequency 60 kHz and ripple need to be less than or equal 1mv so what is the value of capacitance I need?

 

What is the best way besides the best way? I'm going to need to see the circuit.
Post a schematic.

 

How would you share what goes thru two series capacitors? What do you mean by share? What goes thru one goes thru the other.

 

What is the best way besides the best way? I'm going to need to see the circuit.
Post a schematic.

is my question is stupid or what is the wrong in my question? or you do not like my English? or what is wrong?

 

How would you share what goes thru two series capacitors? What do you mean by share? What goes thru one goes thru the other.

the voltage across the 2 capacitors is 800 vdc and each capacitor is 470uf and 450vdc , so I need to make sure that each capacitor has about 400vdc

 

the voltage across the 2 capacitors is 800 vdc and each capacitor is 470uf and 450vdc , so I need to make sure that each capacitor has about 400vdc

If the two caps are the same value, then they will form a voltage divider with equal voltage drop across each.

 

If the two caps are the same value, then they will form a voltage divider with equal voltage drop across each.

the cap. has 10% tolerance

 

The best way is to add the two resistors across the caps like you said. I dont know of any other way.

 

https://www.illinoiscapacitor.com/pdf/Papers/voltage_balancing_resistors.pdf
Edit:
I suppose you could also use zener diodes.

 

the cap. has 10% tolerance

Then put one 15-20 watt 22kΩ resistor across each capacitor.

 

The best way is to add the two resistors across the caps like you said. I dont know of any other way.

I need to avoid the dissipation on the resistor .do you think if we but zener it will work or may be one conduct first and scroe the balance