Basic condition for oscillation

Discussion in 'General Electronics Chat' started by athulascc, Mar 1, 2015.

Aug 15, 2014
88
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I have learned that there is two basic conditons for sustain oscillation

1. A(w)b(w)=1 (loop gain=1)
2.phase shift of 0 or multiple of 360

but to start A(w)b(w)>1

why those conditions? how to understand that?

2. Dodgydave AAC Fanatic!

Jun 22, 2012
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For an oscillation to start an amplifier has positive feedback .

3. GopherT AAC Fanatic!

Nov 23, 2012
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@athulascc

Because all other conditions will either dampen the oscillation or cause a stable saturation condition at the positive or negative rail.

Apr 5, 2008
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Hello,

Have a look at the following PDF:

Aug 15, 2014
88
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yes @Dodgydave , but if A(w)b(w)>1 at the start then how it becomes =1 when oscillation?
when we design we can't make actually A(w)b(w)=1 , but how it oscillate?

@GopherT I am trying to find theory behind these two conditions?

Aug 15, 2014
88
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@bertus thanks.that contains what I am looking for.

7. Brownout Well-Known Member

Jan 10, 2012
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You don't really need to worry about that. The amplifier's gain will, at some point, decrease to the point where loop gain will = 1. At that point, you have sustained oscillation.

8. GopherT AAC Fanatic!

Nov 23, 2012
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I thought it was obvious.
Any phase shift not = 360 degrees (or multiples) will cause the gain of 1 condition to not be true at various times in the oscillation period.
Any gain below 1 will cause the signal to dampen each oscillation.
Any gain over 1 will cause signal to saturate after some number of oscillations.

9. ErnieM AAC Fanatic!

Apr 24, 2011
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A gain of 1 will sustain an oscillation, but that is of little use at start up when there is no oscillation. So a gain >1 is required to start.

Once an oscillation begins a gain >1 will indeed produce saturation; saturation is a non-linear condition with a side effect of limiting gain, so the now distorted (or clipped) signal will be running about with a gain of precisely 1.