Can a 500Ω potentiometer be placed in series with R3, and the user can fine tune the amplitude to a fixed, say, 3v by taking advantage of the precision rectifier??

Yes, a pot can be used to vary the output amplitude.

But what do you mean "taking advantage of the precision rectifier"?

 

Yes, a pot can be used to vary the output amplitude.

But what do you mean "taking advantage of the precision rectifier"?

By delay i meant how long it took to finish 1m tran, which takes 1 sec if you use LT1013.

The precision rectifier is part of the design to measure the voltage across the components ( a resistor and the unknown inductor) which shows real peak as opposed to multimeters set to AC range which show RMS.
This completed design is supposed to be a make-shift inductance meter

 

So where's this long delay you mentioned?

I think she is referring to my post #73, which goes back to post #59.

In a circuit such as your post #61, inadequate filtering of the rectified output signal at node AGCb can cause the remaining ripple to modulate the gain control device, adding harmonic distortion to the output signal.

ak

 

This completed design is supposed to be a make-shift inductance meter

Are you using a microprocessor to calculate the inductance?

 

By delay i meant how long it took to finish 1m tran, which takes 1 sec if you use LT1013.

If you are referring to the oscillator with the AGC circuit, that has nothing to do with the op amp model, it's the time-constant of the AGC control loop.

Otherwise, in general, the time it takes to do a simulation is determined by the frequency of the voltage changes in the circuit, i.e. a circuit oscillating at 1MHz will take a long longer for a 1ms simulation, than a 1kHz oscillator.

 

Are you using a microprocessor to calculate the inductance?

no. Just the equation.


View attachment 1778944096771.jpeg

 

This is what Theory says but I am concerned about the power supply's series resistance which can throw off the super diode measuring

 

This is the op-amp based super diode but R1 must be exactly the same as R2