Good. Check at pin14, should see the same 5 volts.

Yes. Is it the raise curve or current ?

 

Yes. Is it the raise curve or current ?

What does that mean?

 

What does that mean?

Is the 0 to 5v curve too smooth, so it does not trigger ?
Is the current too low, so it does not trigger ?
(I have ordered a CD4017BE and LM555 just in case)

 

Is the 0 to 5v curve too smooth, so it does not trigger ?
Is the current too low, so it does not trigger ?

Shouldn't be. The chip I used was a 4017BE so maybe there is a difference.

 

Shouldn't be. The chip I used was a 4017BE so maybe there is a difference.

Annoying detail. Wonder if the BE has a schmitt trigger on the clock input ?

 

Wonder if the BE has a schmitt trigger on the clock input ?

It does.

 

It does.

Probably why. Thanks

 

Is it that old ? Should I use another ?

Not necessarily any problem, it was just surprising so see such and old chip. That one dates back to my first experience with CMOS, back in the "caveman" days of SSI logic circuits.

 

Use a 10K resistor to pull down the Pin 14, no need for a series resistor if the pull-up is the same voltage as pin 16 supply voltage. Also, tie the capacitor to common instead of V+

 

MisterBill2 version: Another version to try:

 

MisterBill2 version: Another version to try:
View attachment 290180View attachment 290181

Only MisterBill2 version works. Why ? Does it work with all 4017 ic ?

 

Only MisterBill2 version works. Why ? Does it work with all 4017 ic ?

With the 100K and the 0.1Mfd cap, the rise time on the input will be slow. Some versions of CMOS logic devices do not like slow rising inputs. That could be the reason. OR, it does not rise to the trigger threshold before the button is released.
Also, some CMOS ICs just will not work with high value series input resistors.
And YES, my input will work with all 4000 series CMOS devices. At least, those using either 5 volt or 12 volt supplies.

 

Thanks. Lastly, how can I connect a (button) LED to the gate of Q2 ?

 

If this is referencing the circuit in post #128, the answer is "not directly". Also, it does not seem that the mosfet will be adequately driven because of that series resistor. That should be a diode, because you have a functional OR gate driving the mosfet gate.
In fact, why not power the CMOS logic with 12 volts? That will provide better gate drive to the switching transistors.
What is the reason for adding an LED??

 

If this is referencing the circuit in post #128, the answer is "not directly". Also, it does not seem that the mosfet will be adequately driven because of that series resistor. That should be a diode, because you have a functional OR gate driving the mosfet gate.
In fact, why not power the CMOS logic with 12 volts? That will provide better gate drive to the switching transistors.
What is the reason for adding an LED??

12v is fine for me (less heat from voltage drop). Please suggest best SIMPLE low sleep power curcuitry (runs on 6x21700 li-ion batteries). (Button) LED for indicating audio power on.

 

why not power the CMOS logic with 12 volts?

The IRLZ44N is a logic level mosfet.
R7 acts as a pull down when pin 3 is low and eliminates the diode.

 

Ok. Thanks. What does C4 and C5 do ?

 

Ok. Thanks. What does C4 and C5 do ?

Required filter capacitors for the 5 volt regulator chip.
Connecting LED to gate of Q2.

 

Required filter capacitors for the 5 volt regulator chip.
Connecting LED to gate of Q2.
View attachment 290202

Thanks. I will use this.

 

The connections to the 4017 counter do not look right to me. From post #1 I get these:
1. off
2. audio on
3. audio and lighting on.
That will not be possible with the circuit as shown.
But pin3 is high when the counter resets to zero, and that will not be the "everything off" condition. So really, pin 3 should have no connection, Pin #2 is high at the count of "one", and so it should feed the gate of Q2 through a diode, to allow Q2 to also be switched on through another diode for the count of 2, when pin 4 is high. That would be a diode "wired OR" function, required to hace the audio power on for conditions #2 and #3.
R2, used as a pull-down resistor to switch the mosfet off, needs to connect to the gate and to the common, NOT another CMOS output.
As shown, there is no "everything off" option available. With the 4017 decimal counter, one of the ten outputs is always high.