I'm looking for a pre-designed chip with ultra low power consumption working with 12V. Giving one pulse each day. No accuracy is needed (+/- 3 hours). I have tried build it with 4060, but the current is over 1mA.
Excuse for my non native English.

 

Quiescent current of CD4060 is 10 μA with 10 V supply. You must be doing something wrong.
Current consumption goes up with frequency. Use a lower clock frequency.

 

The 4060 has a CMOS oscillator, which means the clock input pin is at intermediate voltages, (i.e. not Vss or Vdd) which causes the device to draw current, as both FETS get switched on.
The 4521 is similar but has the ability to insert resistances in series with the oscillator to reduce the consumption.
Also the 4060 will use a lot less current on a lower supply voltage. The Vgs(th) for its MOSFETs is about 1.5V, so at a 3V supply there should be almost zero cross-conduction current.

 

Thanks alot for quick answers!

 

For very long periods with low consumption the CD4521 and CD 4541 are much better choices.

 

Tanks. Will check it up.

 

I'm looking for a pre-designed chip with ultra low power consumption working with 12V. Giving one pulse each day. No accuracy is needed (+/- 3 hours). I have tried build it with 4060, but the current is over 1mA.
Excuse for my non native English.

What qualifies as "ultra low power consumption"?

Why 12 V?

The more information you provide about what you actually need, the more relevant the suggestions you get are likely to be, but by limiting the suggestions that just don't apply to your situation and also by encouraging suggestions about other ways of achieving your actual needs in alternate ways.

 

It's because I will open a 12 V valve a few seconds per day and just want one power source. I think a voltage regulator will eat some of the battery time? Most likely I have found how to do it with help of previous answers.

 

For very long periods with low consumption the CD4521 and CD 4541 are much better choices.

Why?

 

They have longer divider chains.
From memory, I am on my phone, they have 24 stages instead of only 14 stages of the 4060.
They have also integrated power on reset and other features

 

It's because I will open a 12 V valve a few seconds per day and just want one power source. I think a voltage regulator will eat some of the battery time? Most likely I have found how to do it with help of previous answers.

What are the resistor and capacitor values in the oscillator circuit?

You could also use an 8-9V Zener diode in series with the power to the CD4060 circuit to reduce its voltage and thus the current draw, with no added current draw from the Zener.
A transistor at the 4060 output could then power the valve from 12V.

 

How about using an ATtiny85 processor? The default clock frequency is 8MHz but you can drop it to 1MHz to reduce current. Put a delay() loop within a delay() loop to delay 24 hours (remembering that delay(1000). delays 8 seconds when the clock speed is reduced). This would also allow you to program how long the valve stays open, and/or use a pot to adjust this time. A further trimpot could be used to adjust the 24 hour time delay.

 

How about using an ATtiny85 processor?

Would that use less than a mA of power at a 1MHz clock, which the TS wants?

 

Would that use less than a mA of power at a 1MHz clock, which the TS wants?

The TS has only indicated that 1 mA is too much, they haven't answered my question about low they need the current to be, nor given the information needed to estimate it, such as the battery that is powering it and how long they need the battery to last, plus how much current is needed to operate the valve and how many seconds is "a few seconds" each day.

 

Would that use less than a mA of power at a 1MHz clock, which the TS wants?

Fair point. As I described it, using delay(); for timing it consumes about 2mA but with a bit more complicated code you can put it into a sleep mode with a watchdog timer to wake it up at specified intervals. Whilst asleep it’d consume around 5uA.

 

you can put it into a sleep mode with a watchdog timer

What current does the watch dog take?

 

What current does the watch dog take?

From the data sheet:

 

Before someone else asks, if it’s powered via a 390K resistor in series with a 3.9V zener diode pulling 20uA how will it turn on the transistor to turn on the valve?

I think the answer is that the zener needs a parallel capacitor with sufficient charge that when the processor wakes up it can quickly turn on another transistor to reduce the 390K resistance value so enough current is available? To kick start, a tact switch to do the same job as that transistor.

 

I'm probably just talking to myself now, but I got t thinking, there must be a way IOT transmitters can consume very little power whilst sending measured values infrequently.

And I stumbled across the TI Nano-Power system timer TPL5111 which consumes just 35nA. Maximum delay of two hours, so when it turns on the supply to the processor the code would need to increment an EEPROM value by 1 until that value reaches 12 when the valve could be activated. A "DONE" signal back to the TPL5111 would then shut down the processor power.

Adafruit does a breakout board to make life easy

 

I downloaded the TPL5111 datasheet, and found a small mistake....I used the submit documentation feedback link to report it.
Can you spot it? Attached the schematic in question.