Is that an initial condition (.IC) element connected to the transistor base in your circuit diagram? If so, why do you need to set it to 5V? The current source would try to sink the 1mA and the Ib and Ic would start conducting across the base-emitter and collector-emitter junctions on their own and reach a DC balance without any .IC condition or adjusting the current source resistance.Originally posted by JoeJester@Jan 11 2006, 05:37 PM
So as I was revising the simulation, it came to me that the transistor would have to overcome the 1 mA current generator before the transistor could begin to conduct.
The current source internal resistance is set to infinite. Changing it to 1M didn't make much of a difference.
Anyways ... what am I missing in the simulation?
[post=13044]Quoted post[/post]
What simulation program (SPICE) are you using?
I've attached a partial output listing (I've cut out most of the rubbish and license info) of HSPICE run of the circuit below. Feel free to have a browse. Note that with the BJT model that I used I obtained:
Vb=1.92V
Ve=1.23V
Vc=1.54V
Vbe=0.69V
Ib=0.31mA
Ic=0.69mA
Those values might be a little bit difficult to find in the listing, but they are mostly under the *** operating point information **** heading.