They can go above 1A with a beefy heat sink.

LM7805 will go into current limit. The only reliable way to get more is to use an external pass transistor.

 

They can go above 1A with a beefy heat sink.

By the way would you mind where in the circuit that you provided the current 1.5 Amp is generated? just for my understanding...how is the circuit produce that much amount of current

 

It doesn't produce current. Current is set by "ratio" of voltage and resistance.
If your battery is capable of providing 1.5A then it has a potential to provide 1.5A but the current drawn is dependent on load.

Ohms Law

 

based on the datasheet it should produce at least 5 volt or a little more like 5.2 volts..

that's a weird spec for a regulator.

can you show a screen shot of the datasheet?

 

that's a weird spec for a regulator.

can you show a screen shot of the datasheet?

Did you read any of the responses already posted to this thread?

 

LM7805 will require a heat sink if high currents are drawn.

I have another question is the capacitor exact rating 330nf and 100nf are compulsory? because i dont have with those rating...can i use anything small or larger capacitance

 

Pretty much any value capacitor will work as long as its not too large and small in ranges of pF.

 

I have another question is the capacitor exact rating 330nf and 100nf are compulsory? because i dont have with those rating...can i use anything small or larger capacitance

Those values are optimum according to the datasheet, but as you have seen, the regulator will often work without them. 100nF caps are used very often across the power pins of ICs, are not expensive, and you should get some to have on hand. One of those on the input and another on the output would be better than nothing.

 

Pretty much any value capacitor will work as long as its not too large and small in ranges of pF.

Today finally i tested your circuit...using 9 volt battery and the output is way too far off what i've expected. It's only output 3 volt...However using 16 volt to 18 volt it does provide 5 volt...so i think 9 volt is not enough to charge a phone using the circuit

 

Today finally i tested your circuit...using 9 volt battery and the output is way too far off what i've expected. It's only output 3 volt...However using 16 volt to 18 volt it does provide 5 volt...so i think 9 volt is not enough to charge a phone using the circuit

9V battery is just 6 AAA batteries in series. it has very little current, and that's why your voltage on 7805 was low. If you connect few 9V batteries in parallel, it will work just fine.

 

AAA batteries have more current capability than 9V.

 

Hello,

@bushrat , actualy they are even smaller as AAA.
See these pages for more info:
http://www.rfcafe.com/references/electrical/aaaa-cells-inside-a-9volt-battery.htm
https://en.wikipedia.org/wiki/Nine-volt_battery

Bertus

 

9V battery is just 6 AAA batteries in series. it has very little current, and that's why your voltage on 7805 was low. If you connect few 9V batteries in parallel, it will work just fine.

Its interesting i tested using a different cable and it is now generating 5 volt i am very happy and thank you all...my questions is answered perfectly

 

@bushrat , actualy they are even smaller as AAA.
Bertus

I stand corrected..

 

The small caps 0.01-0.1 uF are usually ceramic because of their higher frequency response. They need to be located close to the regulator.
They effectively compensate for the inductance of the wire or trace so there is less tendency to oscillate. These are typically called "bypass capacitors". In some cases, bypass capacitors are parallel combinations of various types of capacitors. In general, go with what the manufacturer suggests or use 0.1 uF caps on nearly all the supply pins of every IC you use.

 

I'm late to this one, but I used this voltage reference in a proof of concept device and it was extremely accurate:

http://www.digikey.com/product-search/en?keywords=LT1236BIS8-5#PBF-ND

The data sheet has an example circuit that uses an external transistor to boost current capacity of the circuit.

 

I'm late to this one, but I used this voltage reference in a proof of concept device and it was extremely accurate:

http://www.digikey.com/product-search/en?keywords=LT1236BIS8-5#PBF-ND

The data sheet has an example circuit that uses an external transistor to boost current capacity of the circuit.

Thank you mr.software despite of your late reply but it is not wasted and very useful info for me.