Ok I think I might just be getting confused because the Vs is in front of the 5ohm, rather than behind it. Doesn't make a difference does it? Like I could easily switch those around, could I? Relative to the V1 it's the same, right?
What about this current in green, designated i.
Is that the same as Ix? Ix is given in the question. What I mean to ask is, is ix coming to that node at V1? no matter what. Or is the current coming from that right hand branch, is that current infact:-
ix + (Vs/5ohm)?
Or maybe
Vs/5ohm = -ix?
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