So I am dabbling with some integrated circuits and need some help....
Say the Voltage Input High Min Value is 2V, the Max is 5 V.... If I had a 5v source and wanted to approximate the voltage on the pin to be 2.4 Volts would I calculate it as
-5 + r(0.005) + 2.4 = 0
r(.005) = 2.6
r = 520 ohms
Or would that be wrong.... I know the Input Leakage current is 10uA so really nothing to worry about... but lets say I wanted to pull it down, what is a reasonable way to do this formula wise... I don't want to be told to just use a fairly large resistor, rather I would like to know how it is calculated.....
would you want it so that....
VLmax > Ilkg * Rgnd > VLmin or what?
Say the Voltage Input High Min Value is 2V, the Max is 5 V.... If I had a 5v source and wanted to approximate the voltage on the pin to be 2.4 Volts would I calculate it as
-5 + r(0.005) + 2.4 = 0
r(.005) = 2.6
r = 520 ohms
Or would that be wrong.... I know the Input Leakage current is 10uA so really nothing to worry about... but lets say I wanted to pull it down, what is a reasonable way to do this formula wise... I don't want to be told to just use a fairly large resistor, rather I would like to know how it is calculated.....
would you want it so that....
VLmax > Ilkg * Rgnd > VLmin or what?