Welcome to AAC!

You're going to have to provide a lot more information if you expect anyone to understand what you're talking about.

 

Usually a lamp is connected to the output of a power supply, not to the input.

 

A Lamp in series with the Input of a SMPS
can very easily cause an UVLO problem, ( Under-Voltage-Lock-Out ).

What is the Part-Number and manufacturer of your Power-Supply ?,
and why are You putting a Lamp in series with it ?
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@WBahn
This thread makes no sense anymore since TS cut the OP out and pasted it into a new thread. Very bizarre thing to do. It would make more sense to me if this thread were closed instead of the new one.

@Kava Canada
A lamp in series with a power supply is a strange thing to do. It will only light when sufficient current goes through it. Apparently in your case the power supply does not draw enough current to keep the lamp lit continuously. Try attaching some loads to the power supply outlet and see if it gets "better."

"Better" in quotes because I do not consider less flashing to be a positive outcome if it comes at the cost of waste to power unnecessary loads.

Just put the lamp in parallel with the power supply.

 

A Lamp in series with the Input of a SMPS
can very easily cause an UVLO problem, ( Under-Voltage-Lock-Out ).

What is the Part-Number and manufacturer of your Power-Supply ?,
and why are You putting a Lamp in series with it ?
.
.
.

First of all thanks for your cooperation. I installed it to check if there is a short, you can say like protection

 

@WBahn
This thread makes no sense anymore since TS cut the OP out and pasted it into a new thread. Very bizarre thing to do. It would make more sense to me if this thread were closed instead of the new one.

No, the OP was always a blank post. The title is (presumably) the question.

 

First of all thanks for your cooperation. I installed it to check if there is a short, you can say like protection

and the power supply is Motorola ARTESYN Modle AA25930L-A

 

No, the OP was always a blank post. The title is (presumably) the question.

Nothing about this is normal.

 

First of all thanks for your cooperation. I installed it to check if there is a short, you can say like protection

That is not a way to protect a circuit or to tell if there is a short. You should remove the lamp and install a fuse or breaker.

 

What type of lamp did you use - incandescent, LED or fluorescent? What voltage and power is the lamp? What is the voltage of your AC supply? If you can supply this information, we may be able to answer your question.

 

What type of lamp did you use - incandescent, LED or fluorescent? What voltage and power is the lamp?

It was in a series and the lamp was Halogen

 

It was in a series and the lamp was Halogen

That is only the answer to first question I asked. How about the rest?

 

That is only the answer to first question I asked. How about the rest?

The voltage is 115 VAC and I connect it like that . one line directly to the power supply and the other line to the lamp and from the lamp to the power supply

 

The voltage is 115 VAC and I connect it like that . one line directly to the power supply and the other line to the lamp and from the lamp to the power supply

the lamp voltage is 115vAC 100W

 

the lamp voltage is 115vAC 100W

Now we have enough information to make a guess at the answer to your question:
A halogen lamp has a tungsten filament. A tungsten filament has very low resistance when it is cold. The resistance increases by about ten times as it heats up to its working temperature.
The power supply will have an inrush current when it is first turned on. This current will flow through the lamp, heating the filament and making it glow. As the filament approaches its working temperature, the resistance will increase, causing more voltage to be dropped across the lamp, so less will appear across the supply. It will reach a point where the voltage is below the dropout voltage of the supply so it will shut down. When it does, it will stop drawing current, so the lamp will extinguish. The filament will cool down, reducing the resistance across it. When the resistance of the lamp is low enough, the supply will start drawing current again, so that will cause the cycle of flashing on and off.
Pulsing the AC to the power supply is not a very nice thing to do. It can destroy it very quickly.

I hope this answers your question and I hope your power supply survived your experiment.

 

Aren't inefficient incandescent light bulbs banned from sale now? My home still has a few that have not burned out yet.

 

Now we have enough information to make a guess at the answer to your question:
A halogen lamp has a tungsten filament. A tungsten filament has very low resistance when it is cold. The resistance increases by about ten times as it heats up to its working temperature.
The power supply will have an inrush current when it is first turned on. This current will flow through the lamp, heating the filament and making it glow. As the filament approaches its working temperature, the resistance will increase, causing more voltage to be dropped across the lamp, so less will appear across the supply. It will reach a point where the voltage is below the dropout voltage of the supply so it will shut down. When it does, it will stop drawing current, so the lamp will extinguish. The filament will cool down, reducing the resistance across it. When the resistance of the lamp is low enough, the supply will start drawing current again, so that will cause the cycle of flashing on and off.
Pulsing the AC to the power supply is not a very nice thing to do. It can destroy it very quickly.

I hope this answers your question and I hope your power supply survived your experiment.

Thank you very much, I really appreciate your help and kindness