Work out the voltage on each side of the bridge using ohms law, then subtract one side from the othe to give the voltage across the meter, and that will give you its current and direction.
Except that since the bridge isn't balanced you can't use Ohm's Law to determine the voltage on each side of it.Work out the voltage on each side of the bridge using ohms law, then subtract one side from the other to give the voltage across the meter, and that will give you its current and direction.
First, this is homework, so just offering up answers doesn't help the TS learn.1.5mA?
First, this is homework, so just offering up answers doesn't help the TS learn.
Second, ask if your answer makes sense. Look at the original circuit and determine whether ig, as the TS defined it, will be positive or negative?
Next, put some bounds on what the answer can be by determining the voltage across the galvanometer assuming that it has infinite resistance. The absolute most current that could possibly flow in the galvanometer would be this voltage divided by the actual galvanometer resistance.
Just guessed i am not sureFirst, this is homework, so just offering up answers doesn't help the TS learn.
Second, ask if your answer makes sense. Look at the original circuit and determine whether ig, as the TS defined it, will be positive or negative?
Next, put some bounds on what the answer can be by determining the voltage across the galvanometer assuming that it has infinite resistance. The absolute most current that could possibly flow in the galvanometer would be this voltage divided by the actual galvanometer resistance.
Please don't just throw out guesses in someone else's homework thread. People start such threads because they are struggling with some aspect of it and random guesses not only don't help, but they are likely to confuse the TS.Just guessed i am not sure
Previous experience indicates that the chance for success is very low.Can you teach me?