Looking for a resistor that will match the resistance of a 40 watt incandescent light bulb. I have a smart home lighting system (Lite Touch) I am working on for a client. Lite Touch has recently gone out of business so there is no longer tech support available. I am replacing many of the light fixtures with LED lamps and have come across a problem. This system uses triac type dimmers that are located in dimmer modules that are remote from the low voltage switches located in each room. This is a $50K system that my company installed around 2006. The problem is that the triac dimmers leak enough power to get the LED lamps to fire so that when the switch is pressed to turn the lights off they go to a dim level and never fully turn off. I have explored many options and due to the manufacturer being out of business and parts no longer available I have narrowed it down to one solution. When I leave the equivalent of a 40 watt incandescent fixture in the lighting circuit that is enough power draw to allow the LED lights to turn completely off. In some areas I simply leave one of the less efficient lamps in place. But in some area this is not possible as recessed lighting wont match and the owner will not go for that. So I need to install a resistor in the lighting control panel the is the same draw or more of a 40 watt incandescent lamp. I figure a wire would resistor with an aluminum heat sink will work best as this load may be on for hours and maybe even days if they leave town and forget to turn the lights off. I just need help sizing. Simple ohms law can decide the amount of resistance needed but I am not savvy enough with electronics to safely know what wattage and size resistor to look for. The system is 120 Volt AC. Thank you anyone for any help with this.