I meant to say current XD.Hello,
As the resistors are equal, the output voltage will be 1/2 the input voltage with no load.
As the resistors are quite large the voltage will drop when a load is connected.
Bertus
You made a mistake in your algebra.I know V = I(R) and I = V/I
This doesn't make sense. Please attach a schematic.I want the bottom output to be alone, and the top to go to ground. Sorry, forgot to include that!
Just the top alone. I want the bottom connected to ground. Sorry, its been such a long day.Hello,
Wich current do you want to know?
Bertus
Well, I know that whatever it is before load, I can use the series equation, but if it was connected alone to ground, what would it be?Hello,
What will be the load, as that will influence the output voltage and the total current.
Bertus
I mean the middle one while both are connected to ground. Sorry, I gotta be honest. I'm really bad at this. I'm studying over the summer but in my textbook, I just guess I'm stuck. Here, I will redraw a schematic and attach itHello,
Do you mean the short circuit current?
When the output is shorted, there will be no voltage accross the bottom 10K resistor.
The current will be 30 Volts / 10K Ohms = 3 mAmps.
Bertus
His problem was with algebra, not Ohm's Law.Ohm's law is something that you must learn first and then deal with electronics.
I know V = I(R) and I = V/I
In the circuit in the first picture; both.OK you guys, help out an old dummy, me. Which resistor sets the output current in a voltage divider? Top or bottom?
Both. Current from the center node of a voltage divider into an external load of some kind is determined by the load - in parallel with the bottom resistor and in series with the top resistor. To see how the two resistors combine to affect the output, see this:OK you guys, Which resistor sets the output current in a voltage divider? Top or bottom?
by Aaron Carman
by Duane Benson