so does that make the final answerC1||C2 = 1/(1/C1 + 1/C2)
correct me if i am wrong. If I neglect R in the circuit then C1, L and C2 are in series right?C1 + C2 = 1/(1/C1 + 1/C2)
and where does it say C1=C2=C?
so does that make the final answer
Ls/(Cs/2 +Ls) ??
They are in series whether you neglect R or not.correct me if i am wrong. If I neglect R in the circuit then C1, L and C2 are in series right?
im sorry my bad. not solution but an equationThat is not even a solution because C is undefined.
so if C1, L and C2 are in parrallel, then rewrite the equation with respect to the impedance then does this makeThey are in series whether you neglect R or not.
The answer is not dependent on R.
Where in that circuit is there a component called C? There is none.so if C1, L and C2 are in parrallel, then rewrite the equation with respect to the impedance then does this make
1/Cs + Ls + 1/Cs right?
It is a complex number used as the frequency parameter in Laplace transforms. I am glad you know it does not stand for series. So moving on....Its a transfer function. from time domain to s-domain. that is what s means
there were no given values of each component. What you see is what you get . Its just a constant variable.It is a complex number used as the frequency and phase parameter in Laplace transforms. I am glad you know it does not stand for series. So moving on....
What is the solution to your circuit?
AND.
If:
R = 2000 ohms
C1 = 3 F
C2 = 6 F
L = 5 H
What is the transfer function?
As has already been noted, you can't just assume that C1 and C2 have the same value. So your solution must reflect this reality.so if C1, L and C2 are in parrallel, then rewrite the equation with respect to the impedance then does this make
1/Cs + Ls + 1/Cs right?
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