# Urgent ! Please who can solve this ?

Discussion in 'Homework Help' started by blogs4world, Aug 19, 2014.

1. ### blogs4world Thread Starter New Member

Aug 19, 2014
3
0
I am stuck here. Can anyone please solve this for me.
You can do the math in a page and take snap and attach here please.
I am attaching the circuit here

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2. ### djsfantasi AAC Fanatic!

Apr 11, 2010
3,496
1,253
Show your work so far. Then, we can see where you are "stuck". This forum is not "Homework Done For You".

3. ### tshuck Well-Known Member

Oct 18, 2012
3,527
675
We are not a homework solving service.

We will help (read "not do it for you, but provide insight") you with your homework once you make an honest attempt at the answer and show it here.

4. ### blogs4world Thread Starter New Member

Aug 19, 2014
3
0
I tried this more than 20 times. If there is only dependent voltage source then I can solve it easily but when there is dependent current source then it is tough.
When considering 25V source then the formula comes on 1st loop...
25-24(i1)+4(i2) = 0
but in the 2nd loop there is one current source how to apply there KVL ?
-4(i2)+4(i1)-0.1(vx) = 0 ??? since 0.1vx is a current, how to count it as a volt?

But when I am considering 5A is active
then 1st loop should be ??

Really it is heck to me. Can anyone help me please?
I took help of B.L thereza book but there is no such an example and no KCL OR KVL applied but a critical formula applied. if you can help me to understand then i will be grateful to you

5. ### blogs4world Thread Starter New Member

Aug 19, 2014
3
0
I did it in my notebook but stuck on dependent current source. if there is voltage then i can solve but current

6. ### MikeML AAC Fanatic!

Oct 2, 2009
5,451
1,071
I did this a different way:

I just summed the current into node X.

(25-Vx)/20 + 5 -Vx/4 + 0.1*Vx = 0

Multiply through by 20
25 - Vx + 100 - 5Vx + 2Vx = 0

Solve for Vx
125 = 4Vx

or Vx = 31.25

To double check:

• ###### D187.jpg
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Last edited: Aug 19, 2014