Say i have an boolean equatio could anyone help me simplify it?

Z = D'(ABC' + A'B'C + AB'C + A'BC + ABC)

If possible could you also show your working out? thnx alot

 

If this is a homework question, we could move it to the more appropriate forum. Just let us know.

 

The OP should refer to the Boolean Algebra section here on AAC; in particular the rules for simplification section.

Have a go at the answer and feel free to post up your attempts.

Dave

 

If A/A'=0, which I am not sure of, I do not think this is correct. then the whole thing cancels out to 0.

If not, please tell me what A/A' is...

If it is 0, I will show you what I did, kinda senseless if it's not b/c my first step includes it...

 

If A/A'=0, which I am not sure of, I do not think this is correct. then the whole thing cancels out to 0.

If '/' means division, then this doesn't make any sense, since division isn't defined for Boolean quantities. The only binary operations are AND (using juxtaposition or *, as in AB or A*B) and OR (using +).

 

hmm didn't know that. I knew something was wrong. So much more to learn

 

here's my try tough i'm nt so sure about it.
Z = D'(ABC' + A'B'C + AB'C + A'BC + ABC)
Z= ABC'D' + A'B'CD' + AB'CD' + A'BCD' + ABCD'
Z= ABD'(C'+C)+B'CD'(A+A')+A'BCD'
Z=ABD'+B'CD'+A'BCD'
Z=ABD'+CD'(B'+A'B)
Z=ABD'+CD'(B'A')
Z=ABD'+CD'B'A'
Z=D'(AB+A'B'C)
Z=D'(ABC)
z=ABCD'

 

dhamphire,

ABC'D' + A'B'CD' + AB'CD' + A'BCD' + ABCD'

Using the logical values of 2,6,10,12,14 and the Quine-McCluskey method, I get ABD' +CD' . Look at your 5th line. B'+A'B = A' + B' , not B'A' .

Ratch