Hi sexy guys and girls out there..
I am to design a square wave generator.
I am given the following components:
1. 230V/6-0-6V transformer with 3-pin plug
2. ac main supply
3. 1 diode 1N4001
4. parallel RC load
5. IC 741 8-pin DIP OpAmp
6. dc dual power supply
7. Breadboard
8. capacitor 100uF
9. resistors: 100 ohm, 1k, 2.2k, 4.7k, 10k, 47k and 100k.
Requirements:
a. Transformer: Step down the ac main supply using the transformer above by connecting it to the mains.
b. Rectifier: Using the stepped down voltage, produce a negative half wave rectified output using a single diode, resistor 1k ohm and capacitor 100uF.
c. OpAmp Comparator Circuit: Using the rectified (ripple) voltage in (2), produce a square wave (50% duty cycle) using OpAmp comparator circuit. The Opamp IC is to be powered from +/- 15V supplies from the dual dc power supply. The rectified voltage in point (b) is to be fed into V+ and the reference voltage (Vref) is to be fed into V-. The reference voltage is to be tapped from the -15V supply by the Voltage Divider Rule; using the available resistors in point (9) above. The number of resistors used has to be as few as possible.
In addition, I need to draw the circuit in circuit maker software. Anybody knows how to use it?
And also, to answer the following questions:
What is the turn ratio for 230 V/6-0-6 V transformer?
Is the 230 V / 6-0-6 V RMS or peak value?
Show clearly the calculation/selection of resistor values for the comparator circuit in part (c).
Thanksin advance
I am to design a square wave generator.
I am given the following components:
1. 230V/6-0-6V transformer with 3-pin plug
2. ac main supply
3. 1 diode 1N4001
4. parallel RC load
5. IC 741 8-pin DIP OpAmp
6. dc dual power supply
7. Breadboard
8. capacitor 100uF
9. resistors: 100 ohm, 1k, 2.2k, 4.7k, 10k, 47k and 100k.
Requirements:
a. Transformer: Step down the ac main supply using the transformer above by connecting it to the mains.
b. Rectifier: Using the stepped down voltage, produce a negative half wave rectified output using a single diode, resistor 1k ohm and capacitor 100uF.
c. OpAmp Comparator Circuit: Using the rectified (ripple) voltage in (2), produce a square wave (50% duty cycle) using OpAmp comparator circuit. The Opamp IC is to be powered from +/- 15V supplies from the dual dc power supply. The rectified voltage in point (b) is to be fed into V+ and the reference voltage (Vref) is to be fed into V-. The reference voltage is to be tapped from the -15V supply by the Voltage Divider Rule; using the available resistors in point (9) above. The number of resistors used has to be as few as possible.
In addition, I need to draw the circuit in circuit maker software. Anybody knows how to use it?
And also, to answer the following questions:
What is the turn ratio for 230 V/6-0-6 V transformer?
Is the 230 V / 6-0-6 V RMS or peak value?
Show clearly the calculation/selection of resistor values for the comparator circuit in part (c).
Thanksin advance