Hey guys, super simple question. It would help so much if you could explain what I am doing wrong/ not doing.
So in this series circuits
E = 12 V
R1: 2kΩ
R2: 3kΩ
R3: 4kΩ
Rt: 9 kΩ (which i found by simply adding them all)
Now it ask for current. Which I would find by,
I = E / Rt
I = 12 V/ 9kΩ
I = ?
(a)0.10mA
(b)1.0mA
(c)1.0μA
(d)10μA
(e) none of these
------ I'm confused as to whether i just carry that kilo over to the answer or do i apply it (E^3) to the answer i just got? Its a hassle to have to convert everything to a base Amp, Ohm, Watt for every single problem so how would you do it without the converting everything first. How do you treat this problem in a calculator?
So in this series circuits
E = 12 V
R1: 2kΩ
R2: 3kΩ
R3: 4kΩ
Rt: 9 kΩ (which i found by simply adding them all)
Now it ask for current. Which I would find by,
I = E / Rt
I = 12 V/ 9kΩ
I = ?
(a)0.10mA
(b)1.0mA
(c)1.0μA
(d)10μA
(e) none of these
------ I'm confused as to whether i just carry that kilo over to the answer or do i apply it (E^3) to the answer i just got? Its a hassle to have to convert everything to a base Amp, Ohm, Watt for every single problem so how would you do it without the converting everything first. How do you treat this problem in a calculator?
I = E / Rt
I = 12 V/ 9kΩ
I = 1.33333 (kA?)
(calculator) I tried converting after that number after to compare it so that it could be in the form of either mA or μA, as those are the only options in the answers but I really don't know if i'm doing this right.
1.3333E^3 = 1333.3333 mA
or
1.3333E^-6 = 1.3333E^-6 μA
Any help is appreciated! I = 12 V/ 9kΩ
I = 1.33333 (kA?)
(calculator) I tried converting after that number after to compare it so that it could be in the form of either mA or μA, as those are the only options in the answers but I really don't know if i'm doing this right.
1.3333E^3 = 1333.3333 mA
or
1.3333E^-6 = 1.3333E^-6 μA