I am supposed to simplify the following function and implement a two level nor gate circuit:
f(w,x,y,z) = wx'+y'z'+w'yz'

I made a k-map, and the POS form as follows: (w+z')*(x'+z')

A little confused on how to implement in terms of nor now? How do I make the nor gates function as two or gates and an and? Just invert everything?

 

Welcome to AAC!

Please post your work.

It would be easier to read your post if you used all caps for the gates:

How do I make the nor gates function as two or gates and an and?

This is easier to read:
How do I make the NOR gates function as two OR gates and an AND?

 

Thank you, I'm going to look over it some more and repost the question with more details later.

 

If you think of what a NOR gate and it's DeMorgan equivalent do in terms of signal levels it may become clear to you. The following two statement implement the exact same logic function:

1. A HIGH OR a HIGH is a LOW (Basic Definition of a NOR function)
2. A LOW AND a LOW is a HIGH (DeMorgan equivalent of a NOR gate)

Does that help?

 

How do I make the nor gates function as two or gates and an and? Just invert everything?

Yes, by using negative logic. An OR gate with negated output is the same as an AND gate with negated inputs.

 

I am supposed to simplify the following function and implement a two level nor gate circuit:
f(w,x,y,z) = wx'+y'z'+w'yz'

I made a k-map, and the POS form as follows: (w+z')*(x'+z')

A little confused on how to implement in terms of nor now? How do I make the nor gates function as two or gates and an and? Just invert everything?

The key is to apply DeMorgan's Theorem.

It is probably easiest to do graphically (what I call "bubble logic"), but can be done with Boolean Algebra as well.

For instance, if you have A*B and apply DeMorgan's, you have (A' + B')'

You should be able to recognize this as A' NOR B'. If A and B are the OR of two terms, what do you have?