'ABSOLUTE MAXIMUM RATINGS'
I'm concerning about the current which is listed on the above table. If the current of 370mA draws for only one segment when the peak current triggered, then the transistor collector current will allows approx. max. 350mA only. Since, Ib=12V/10K=1.2mA. Does it works effectively if I use this transistor to lit the 16-segment?.
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Per segment. Note that for equal brightness, the longer segments take more current than the shorter ones.Is that 20mA current consumption is for an one segment (Or) for all segments such as B,C,E,F,G,H,J,L,M,N?.
Why are you posting part of the LED readout ABSOLUTE MAXIMUM RATINGS chart again?Hi Crutschow!
The voltage drop across R2 is the same voltage drop as the voltage drop across the diode (the base-emitter junction) of the transistor.Why will there be a 9.4V voltage drop across R1?. The diode drop will be 0.6V to 0.8V only, right?. So, from my understanding, 9.4V should be across R2, and there will be 0.7V drop across the diode.
What I wrote on post #12 is wrong?.

You are wasting your time. He does not understand series and parallel circuits.The voltage drop across R2 is the same voltage drop as the voltage drop across the diode (the base-emitter junction) of the transistor.
View attachment 301224
So if there is a 0.7 V drop across the diode, there must be a drop of 0.7 V across R2 because they are the SAME voltage drop.
Hi Agian!Why are you posting part of the LED readout ABSOLUTE MAXIMUM RATINGS chart again?
As I've stated, that's not where you should operate it.
Hi!You are wasting your time. He does not understand series and parallel circuits.
Of course you need to worry about them -- if you exceed them then the device can fail or have significantly reduced life.Hi Agian!
So, I do not need to worry about the ABSOLUTE MAXIMUM RATINGS. If so, then, can I use the transistor (the one which we discussed in the earlier posts) as a switch to this segment?.
Thank you!
No you do not. If you did you would know the the voltage across the lower resistor and the base emitter junction were the same.Hi!
Do not worry! Bob!
I know series and parallel circuits.
Yes you do need to "worry about them" as you never want to exceed them.So, I do not need to worry about the ABSOLUTE MAXIMUM RATINGS.
I mean... I do not need to worry until unless my application is not exceeding the 'Absolute Maximum Ratings'. Right?.Yes you do need to "worry about them" as you never want to exceed them.
You just never design to use them.
Yes, but you will need a resistor in series with each segment to provide the recommended LED current as determined by the supply voltage and the LED forward-drop voltage.Does this transistor will work in this application as a switch to lit the segments?.
The image you posted is the pinout of the transistor itself. The resistors are part of the integrated circuit, thus you cannot inject or test a voltage at the R1-R2 junction. If you want to experiment, use an input voltage of 5v through a 5K potentiometer connected to pin 1. Connect pin 2 to ground through a 1K potentiometer. Now you can measure the current from pin 3 to ground. You should always have a load otherwise you risk smoking the transistor. Once you get the output (Collector) current and voltage where you want it, measure the resistance of the base and emitter resistors. Work out the math using Ohm's Law to verify your findings.Hello All!
1) How much base voltage and current needs to be applied to draw maximum collector current of 500mA using 'PDTD114EU'?.
2) The half of the voltage will be present after R1 resistor. Right?. If I applied 5V before R1, then after R1 resistor the voltage will be 2.5V, which will applied to the base of the transistor, Right?.
View attachment 301100
The datasheet is attached below.
https://assets.nexperia.com/documents/data-sheet/PDTD1XXXU_SER.pdf

Right.Could you confirm that the rest of the LEDs that are not used/connected to the circuit below won't be damaged, Right?.
Since the maximum voltage required for the segments is 4.7V, how do you expect to reliably light them with only a 4V supply?Could you confirm that the circuit below will work?. (or) do you want me to do any modifications?.
V2 5V crossed on Q1 Vce directly?
It is a European transistor that uses a base current of 1/20th the collector current for a good saturation.That chart is of interest when the transistor is used in the linear region, not when used as a switch.
You need to look at the base current required for saturated operation. Usually this is 1/10 of the collector current.