Transistor Base voltage and Current

Thread Starter

pinkyponky

Joined Nov 28, 2019
373
Hi Crutschow!

'ABSOLUTE MAXIMUM RATINGS'
1692944199597.png

I'm concerning about the current which is listed on the above table. If the current of 370mA draws for only one segment when the peak current triggered, then the transistor collector current will allows approx. max. 350mA only. Since, Ib=12V/10K=1.2mA. Does it works effectively if I use this transistor to lit the 16-segment?.

1692945129005.png
 

BobTPH

Joined Jun 5, 2013
11,516
That chart is of interest when the transistor is used in the linear region, not when used as a switch.

You need to look at the base current required for saturated operation. Usually this is 1/10 of the collector current.
 

WBahn

Joined Mar 31, 2012
32,852
Why will there be a 9.4V voltage drop across R1?. The diode drop will be 0.6V to 0.8V only, right?. So, from my understanding, 9.4V should be across R2, and there will be 0.7V drop across the diode.
What I wrote on post #12 is wrong?.
The voltage drop across R2 is the same voltage drop as the voltage drop across the diode (the base-emitter junction) of the transistor.

1692970936845.png

So if there is a 0.7 V drop across the diode, there must be a drop of 0.7 V across R2 because they are the SAME voltage drop.
 

BobTPH

Joined Jun 5, 2013
11,516
The voltage drop across R2 is the same voltage drop as the voltage drop across the diode (the base-emitter junction) of the transistor.

View attachment 301224

So if there is a 0.7 V drop across the diode, there must be a drop of 0.7 V across R2 because they are the SAME voltage drop.
You are wasting your time. He does not understand series and parallel circuits.
 

Thread Starter

pinkyponky

Joined Nov 28, 2019
373
Why are you posting part of the LED readout ABSOLUTE MAXIMUM RATINGS chart again?
As I've stated, that's not where you should operate it.
Hi Agian!

So, I do not need to worry about the ABSOLUTE MAXIMUM RATINGS. If so, then, can I use the transistor (the one which we discussed in the earlier posts) as a switch to this segment?.

Thank you!
 

WBahn

Joined Mar 31, 2012
32,852
Hi Agian!

So, I do not need to worry about the ABSOLUTE MAXIMUM RATINGS. If so, then, can I use the transistor (the one which we discussed in the earlier posts) as a switch to this segment?.

Thank you!
Of course you need to worry about them -- if you exceed them then the device can fail or have significantly reduced life.

If you use the transistors as switches, then you need to have some other means to control the current to the desired operating level, which should be well below the absolute max ratings. For LED circuits, the simplest way to do that is to use a suitably sized resistor in series with each segment.
 

BobTPH

Joined Jun 5, 2013
11,516
Hi!

Do not worry! Bob! :)

I know series and parallel circuits.
No you do not. If you did you would know the the voltage across the lower resistor and the base emitter junction were the same.

You have demonstrated serious misconceptions here that show you do not understand the basics.
 

Thread Starter

pinkyponky

Joined Nov 28, 2019
373
Yes you do need to "worry about them" as you never want to exceed them.
You just never design to use them.
I mean... I do not need to worry until unless my application is not exceeding the 'Absolute Maximum Ratings'. Right?.

Does this transistor will work in this application as a switch to lit the segments?.
 

radiohead

Joined May 28, 2009
514
Hello All!

1) How much base voltage and current needs to be applied to draw maximum collector current of 500mA using 'PDTD114EU'?.

2) The half of the voltage will be present after R1 resistor. Right?. If I applied 5V before R1, then after R1 resistor the voltage will be 2.5V, which will applied to the base of the transistor, Right?.

View attachment 301100

The datasheet is attached below.
https://assets.nexperia.com/documents/data-sheet/PDTD1XXXU_SER.pdf
The image you posted is the pinout of the transistor itself. The resistors are part of the integrated circuit, thus you cannot inject or test a voltage at the R1-R2 junction. If you want to experiment, use an input voltage of 5v through a 5K potentiometer connected to pin 1. Connect pin 2 to ground through a 1K potentiometer. Now you can measure the current from pin 3 to ground. You should always have a load otherwise you risk smoking the transistor. Once you get the output (Collector) current and voltage where you want it, measure the resistance of the base and emitter resistors. Work out the math using Ohm's Law to verify your findings.
 

Thread Starter

pinkyponky

Joined Nov 28, 2019
373
Hi Crutschow!

The common pin of the 16 segment display circuit has a common anode. So, in this case, can I use multiple transistors for the multiple segments which I want to lit as I shown below?. From the circuit diagram below, my understanding is that the green marked LED's only lit and will turn ON, and other LED's won't be switched ON, it will be OFF only because there is no path to pass the current through GND.

The resistor values that are connected in series to the collector of the each transistor, will be calculated later as per the datasheet recommendations.

Could you confirm that the rest of the LEDs that are not used/connected to the circuit below won't be damaged, Right?. Since there is no path to the current flow. Am I right?.

Could you confirm that the circuit below will work?. (or) do you want me to do any modifications?.

The circuit diagram below is an example one, just to make sure with you that this configuration will work or not?.

Thank you!

1693020100235.png
 

crutschow

Joined Mar 14, 2008
38,513
Could you confirm that the rest of the LEDs that are not used/connected to the circuit below won't be damaged, Right?.
Right.
Could you confirm that the circuit below will work?. (or) do you want me to do any modifications?.
Since the maximum voltage required for the segments is 4.7V, how do you expect to reliably light them with only a 4V supply?
The minimum supply should be at least 6V for the LEDs.
 

BobTPH

Joined Jun 5, 2013
11,516
Normally, you multiplex the different digits by switching both the anode and the cathodes. One anode is selected at a time and all of the cathodes for that anode are set. This allows you to control them all with #segments + #digits pins, instead #segments * #digits.
 

Audioguru again

Joined Oct 21, 2019
6,826
That chart is of interest when the transistor is used in the linear region, not when used as a switch.

You need to look at the base current required for saturated operation. Usually this is 1/10 of the collector current.
It is a European transistor that uses a base current of 1/20th the collector current for a good saturation.
 
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