This is an AC related problem, in an AC system one can indeed see large currents but actually very little power consumption. The current through the winding is out of phase with the voltage across that winding. So just because the DC resistance is 1 Ohm, you cannot infer that the power simply V * I. In an inductor with an applied AC voltage, the current through the winding at the instant the voltage peaks, is in fact close to zero and so is the power - at that instant.I am not very good at the maths bit, but I think if the amp is supposed to draw 600 watts at 240v this should work out at 2.5amp.
If I raise the mains voltage slowly with a variac , I am only putting 120 volts in when I hit 2 amps. This is with all the transformer output fuses removed so none of the PCB's are connected to the PSU.

I suspect that if there really were any kind of short circuit then it would have caused a serious failure already too.
Last edited:


