I have been seeing the transformer Equations written differently.. I just need to know which one on the right one.
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So both is fine to use?There really is no difference between the two.
We are talking about ratios. The ratio of P to S is the inverse of the ration of S to P.
Formulat 1 is usually used to find a voltage, Formula 2 is usually used to express efficiency.I have been seeing the transformer Equations written differently.. I just need to know which one on the right one.
And just how does formula 2 express efficiency?Formulat 1 is usually used to find a voltage, Formula 2 is usually used to express efficiency.
output (secondary) over input (primary)And just how does formula 2 express efficiency?
And how does that have anything to do with efficiency?output (secondary) over input (primary)
Why don't you figure it out. I am not going to expand on Joule's Law that many people have written about in transformer theory. There is plenty of information on that subject online.And how does that have anything to do with efficiency?
How efficient is a transformer that has an output of 120 V and an input of 12 V?
How efficient is a transformer that has an output of 12 V and an input of 120 V?
Can you even make any assertion as to which of these transformers is more efficient than the other?
Perhaps more to the point, what is your understanding of what efficiency even means?
Well, at least it appears you recognize that you can't use those equations to say anything about efficiency.Why don't you figure it out.
Nothing in those equations has anything do to with Joule's Law, which deals with the relationship between the energy converted to heat and the current flowing through a resistance over a period of time.I am not going to expand on Joule's Law that many people have written about in transformer theory. There is plenty of information on that subject online.
That is such a wrong assertion that it's really not even worth commenting on. Not to mention that fact that in BOTH of those equations, have the secondary as the "top divisor" (you might want to look up what a 'divisor' is, by the way). In the first equation, you have the secondary current divided by the primary current, and in the second you have the secondary voltage divided by the primary voltage. So, according to your assertion, both of them are efficiency formulas, and since they are reciprocal of each other, you are therefore claiming that efficiency is always equal to 1/efficiency.The only time when the secondary is the top divisor in a formula is in an efficiency formula.
and its not exclusively the only variable in the top divisor of the formula.
But that is the only time I seen the secondary used in the top divisor of an equation.
I make current transformers that count on turn ratio and current ratio.a transformer ratio has nothing to do with the current.
Didn't you not notice that both equations are the same?Formulat 1 is usually used to find a voltage, Formula 2 is usually used to express efficiency.
yes, did you notice my answer is about when the secondary is in top divisor of the equation?Didn't you not notice that both equations are the same?
In a current transformer the voltage is dependent on both the turns ration and the current. And at all times, a current transformer is a very special case device.I make current transformers that count on turn ratio and current ratio.
and
In a voltage transformer the turn ratio and voltage ratio is true.
All transformers that I have used, when in use have current. There current ratio is the same as 1/turn ratio.a current transformer is a very special case device.
Wouldn't that be that the voltage is dependent on the current, the turns ratio and the burden resistance?In a current transformer the voltage is dependent on both the turns ration and the current. And at all times, a current transformer is a very special case device.