I have a tiny TV by tiny circuits.com.
I am trying to figure out how to keep the tiny TV in the “On” state so that I can turn it on by simply applying voltage.
I am using a remote control circuit board to apply the 3.7 V to the circuit board to power the LCD screen and as long as I keep 5 V going to the USB-C port on the circuit board, the remote control will turn off and on the TV Every time you apply the 3.7 V remotely.
However, when you disconnect the 5 V from the USB-C port, and reconnect it, you must then physically press the power button on the top of the TV.
I want to bypass the push button switch so that all I have to do is remotely apply the 3.7 V and not have to physically press the push button.
Does anyone have this little circuit board/TV or have any insight into my issue?
Thanks in advance for the help.

 

Small signal relay and a capacitor will work.
Value of C1 depends on the relay selected.

 

Thanks for the reply and the help. Here are pictures of the front side and back side of the Switch that I am trying to Bypass. Without a schematic, I am not sure where to solder to on the switch. ?

 

I believe like this.
Check first with the power removed using an ohm meter to verify that those two terminals are not shorted.

 

It looks open. What types and values should RL1 and C1 be?

 

Did you verify it's open with the meter?
R1 is 1K ohm.
C1 depends on the relay coil resistance.
Do you have any 5 volt relays on hand?

 

I did put a VOM on it and it shows open.
Do not have any 5 Volt Relays on hand. Can you possible give me an Amazon Link for the Relay and the Capacitor?
SPST, SPDT, DPDT ??? I see some on Amazon but not sure what to get.

BTW.... I thought holding the button closed would work but it seems to "cycle" when you hold it closed so I guess shorting those two pads will not work. ?

 

How much room is available inside meaning would a relay module like This work?

 

I should be able to fit that.
Do I still need the resistor?

 

Resistor not needed and a 100uf capacitor will do for C1.
I have one of those modules and verified the operation.

 

Thank you for all the help!
I will let you know how this works out.

 

Resistor not needed and a 100uf capacitor will do for C1.
I have one of those modules and verified the operation.

One more quick question. When that relays closes, is it only a "momentary" close because that is what that pushbutton switch does I believe? When I hold the switch closed, the TV will turn on and then off again in about 5 seconds. That is why I figured that I could not simply solder bridge those two Push Button Connections that you show the relay connecting to.
Thanks again for all the help!

 

It closes for appx 1 second.

 

It closes for sppx 1 second.

Perfect! Thanks again. I have ordered the Relay Board from Amazon. Will let you know how it works as soon as I wire it up.

 

A reed relay may be smaller than the one selected. And I did not see any need for that 1K resistor either.

 

The resistor is required to provide a discharge path for the capacitor when using only a relay.
Not needed using the module as the on board components provide a path.

 

Not needed if the voltage supply does not open circuit when switched off. AND 1K would be much to low a resistance in any case.100K would be OK for this application, except it is noteeded because other things on that same 5 volt circuit will discharge the capacitor very rapidly. A 1000 ohm resistor will be a big waste of power.

 

Thanks for all the suggestions and feedback.
The relay should be in this week so I will be able to test it.

 

Not needed if the voltage supply does not open circuit when switched off. AND 1K would be much to low a resistance in any case.100K would be OK for this application, except it is noteeded because other things on that same 5 volt circuit will discharge the capacitor very rapidly.

Except for the fact that the 5 volt USB supply is physically disconnected per post #1.
1K was selected to rapidly discharge the cap which typically could be appx 1000uf using a 5 volt relay.