Thanks. I Kept getting answers that would round to 6k also but was told they were wrongThe resistance from A to B is 6 kΩ.
Thanks for explaining! And sorry if I put this in the wrong categoryThe four resistors on the right half are shorted out. So, do not appear in any calculation. The four resistors on the left half are straightforward. 6K ohms is correct. BTW, there is no rounding required.
(10K || 10K + 10K) || 10K = 6K "||" means "in parallel".
Actually with this equation you gave I keep getting 4K so now what am I doing wrong?The four resistors on the right half are shorted out. So, do not appear in any calculation. The four resistors on the left half are straightforward. 6K ohms is correct. BTW, there is no rounding required.
(10K || 10K + 10K) || 10K = 6K "||" means "in parallel".
Thanks for your help!Take it step by step. The right group is shorted out, so forget about them. In the left group, the diagonal resistor is in parallel with the lower resistor. 10K || 10K = 5K.
That 5K is in series with the top 10K. 10K + 5K = 15K. That 15K is in parallel with the input 10K, so 10K || 15K = 6K.
(10K || 10K) is 5K. Then, 5K + 10K is 15K. Then 15K || 10K is 6K.Actually with this equation you gave I keep getting 4K so now what am I doing wrong?
because(10K || 10K + 10K)=6.6repeating then 6.6K || 10K= 4K ?
by Jake Hertz
by Jake Hertz
by Aaron Carman