Its important to realise that the peak voltage will not be maintained on C1 for the full duration of the rectified half cycle, as soon as you start drawing current from C1.So about 14:1 will give me my peak 12V that I want.
Its important to realise that the peak voltage will not be maintained on C1 for the full duration of the rectified half cycle, as soon as you start drawing current from C1.So about 14:1 will give me my peak 12V that I want.
It's been a long time since I did anything with transformers, but doesn't the inductance go as the turns ratio, not the square of the turns ratio?Again, 12V would be considered a RMS value, so the peak would be approx 17V [ less two diode drops after the rectifier] ie: ~ 15.5Vdc
I would use 10H for the transformer primary and 100mH for the secondary, thats a 10:1 step down, also set the voltage to 169V for the mains.
Is the load only a 10K resistance.?