Here, I want to use Thevenin with those 2 resistors in the base.

How can I combine those two resistors with thevenin or do you have any other better idea to combine them? (circled with red in the picture)

(PS: I don't ask the solution of the question. I'm only asking individually the calculation of those two resistors. Thank you.)

 

Pretend the base is not connected and calculate the voltage at the junction. Then it is equivalent of a source at that voltage with a series resistor that us the parallel combination of the two.

Bob

 

Pretend the base is not connected and calculate the voltage at the junction. Then it is equivalent of a source at that voltage with a series resistor that us the parallel combination of the two.

Bob

After calculating it, I will post my calculation.

Thank you for your help sir

 

Pretend the base is not connected and calculate the voltage at the junction. Then it is equivalent of a source at that voltage with a series resistor that us the parallel combination of the two.

Bob

Here I've just tried but confused.

 

Here I've just tried but confused.
View attachment 240517

Normally I have known this trick only:

 

hi cika,
I guess you know that when are using Thevinin in that way the voltage sources are considered as short circuits.

What do you make the junction voltage of the two resistors.??

Update: with the Base disconnected.!
E

 

hi cika,
I guess you know that when are using Thevinin in that way the voltage sources are considered as short circuits.

What do you make the junction voltage of the two resistors.??

Update: with the Base disconnected.!
E

Hi Eric,
I must apply KVL right?

 

hi,
What do you make the junction voltage of the two resistors.??
Update: with the Base disconnected.!

Consider two resistors in series, one is 30K and the other 60k.
At the 30k end you have 5V and at the 60k end you have -1V, so what is the junction voltage.?

E