hi,
attached are my working. Pls verify if my answer were correct.

first convert norton part to thevenin.
thus the current-ctrl voltage source is 70i & 20Ω in series with the circuit.

to compute V\(_{ab}\),
-10 + 10i + 20i - 70i=0
i= -0.25A

i(20)-(70i)= -5+17.5= 12.5V =V\(_{ab}\)

next to compute I\(_{sc}\)
short the ab terminal,
I\(_{sc}\)= i - 3.5i
v=0,
(-10+v)/10 = -i
i= 1

thus, I\(_{sc}\)= 1 - 3.5 = -2.5A

hence R\(_{th}\)= 12.5/-2.5 = -5Ω

i m wondering if i got them right.

 

It looks as though you forgot to attach your file?

hgmjr

 

It looks as though you forgot to attach your file?

hgmjr

i did..pls check again.
thanks

 

To my knowledge you can't have negative resistance.. so maybe your current shoudlnt be negative because I'm pretty sure you got your voltage correctly

 

remove the load, parallel the resistors until you get a simple series cct, reinsert the load and then calculate....no?

 

is the shorted cct current-ctrl current source a supermesh element?
i m lost at this.

regards,