M Thread Starter mishra87 Joined Jan 17, 2016 906 Mar 12, 2021 #1 Hello Guys, Last edited: Mar 17, 2021
DickCappels Joined Aug 21, 2008 7,171 Mar 14, 2021 #2 The temperature drop across the insulator will be watts x °C/watt. Just add that to your junction temperature.
The temperature drop across the insulator will be watts x °C/watt. Just add that to your junction temperature.