# the maximum symmetrical swing in output voltage

Thread Starter

#### ADCapacitor

Joined Feb 3, 2016
42
Hello
I don't quite understand what does the question mean
So I ask my teacher and he tells me draw the load line first
I try to write down the dc and ac load line equation.
dc:
Id=-Vds/(Rd+Rs) + Vdd/(Rd+Rs)
Id=-Vds/5000 +12/5000
ac:
Vds=Vd-Vs
Vds=-id*(Rd//RL)-id*Rs
id=-Vds/3500

I put Vds=0 and Id=0 to dc load line equation
then I get the x-intercept and y-intercept
But I put Vds=0 and Id=0 to ac load line equation
I get both 0 at LHS and RHS
How to find the x and y intercept and plot the ac load line?

#### WBahn

Joined Mar 31, 2012
26,398
The question is simply asking how large the amplitude of the output signal can be, about the quiescent point, without clipping.

Thread Starter

#### ADCapacitor

Joined Feb 3, 2016
42
The question is simply asking how large the amplitude of the output signal can be, about the quiescent point, without clipping.
Do you mean the amplitude of Vds?

#### WBahn

Joined Mar 31, 2012
26,398
No. Vds is not the output of the amplifier -- Vout is (so Vout relative to ground).

• ADCapacitor
Thread Starter

#### ADCapacitor

Joined Feb 3, 2016
42
thank you
I also have another problem
From the above ac load line equation, I only get the slope of ac load line
How to find the rest part of ac load line ? (x-intercept/y-intercept)
Or is there another method to plot the ac load line?

Similar threads