# the maximum symmetrical swing in output voltage

Joined Feb 3, 2016
42
Hello
I don't quite understand what does the question mean
So I ask my teacher and he tells me draw the load line first
I try to write down the dc and ac load line equation.
dc:
Id=-Vds/(Rd+Rs) + Vdd/(Rd+Rs)
Id=-Vds/5000 +12/5000
ac:
Vds=Vd-Vs
Vds=-id*(Rd//RL)-id*Rs
id=-Vds/3500

I put Vds=0 and Id=0 to dc load line equation
then I get the x-intercept and y-intercept
But I put Vds=0 and Id=0 to ac load line equation
I get both 0 at LHS and RHS
How to find the x and y intercept and plot the ac load line?

#### WBahn

Joined Mar 31, 2012
25,918
The question is simply asking how large the amplitude of the output signal can be, about the quiescent point, without clipping.

Joined Feb 3, 2016
42
The question is simply asking how large the amplitude of the output signal can be, about the quiescent point, without clipping.
Do you mean the amplitude of Vds?

#### WBahn

Joined Mar 31, 2012
25,918
No. Vds is not the output of the amplifier -- Vout is (so Vout relative to ground).

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