test load

Thread Starter

imraneesa

Joined Dec 18, 2014
227
I want to check the driver for current. But I don't want to use LED before it spoil. I want to use some kind of test load so that I can use it and adjust the desired current and then finally will use led. Give me a calculation how to make test load for 1w LED. And if it is 500mW LED what will be the test load.
 

#12

Joined Nov 30, 2010
18,224
P = I E
1 watt = I E
E = IR
1 watt = I squared R
1 watt / I squared = R
Make your load equal to R for 1 watt and 2R for 500 mw.
 

#12

Joined Nov 30, 2010
18,224
We don't know what I is either, or the voltage the LEDs use, or the voltage you have available to make the test.
You give us almost nothing to work with, not even the color of the LEDs, or a part number or source for where the LEDs came from.
 

Thread Starter

imraneesa

Joined Dec 18, 2014
227
We don't know what I is either, or the voltage the LEDs use, or the voltage you have available to make the test.
You give us almost nothing to work with, not even the color of the LEDs, or a part number or source for where the LEDs came from.
Iam using two 18650 batteries. So I know the voltage 3.7+3.7. I want to calculate current. So how much load I can put is my question.
 

eetech00

Joined Jun 8, 2013
3,953
I want to check the driver for current. But I don't want to use LED before it spoil. I want to use some kind of test load so that I can use it and adjust the desired current and then finally will use led. Give me a calculation how to make test load for 1w LED. And if it is 500mW LED what will be the test load.
Hi

You have to decide on an LED to use then find its recommended operating voltage/current from its datasheet.
Then use the info #12 gave to calculate a resistor to use as a test load.

eT
 

#12

Joined Nov 30, 2010
18,224
Mouser 1 watt LEDs range from 140 ma to 400 ma, so voltage must be from 2.5V to 7.14V.
Let's assume 140 ma and 2.5V to make a very safe tester.
7.4V - 2.5V = 4.9V
4.9V/.14A = 35 ohms.
Use 39 ohms, 3 watts to start the LED.
That will give an estimate of its proper voltage and we can work at this, bit by bit.
 

cmartinez

Joined Jan 17, 2007
8,255
Thank you so much guys. I understood finally. God bless you all.
Thanks for your thanks... you can now calculate R using the simple equations that #12 gave you... but after you assemble the circuit, you will probably find out that it will consume less than the 350 mA that you calculated for, since every LED has a voltage drop, and you won't know until you put your circuit together and make some measurements, the you can recalculate R
 

Thread Starter

imraneesa

Joined Dec 18, 2014
227
Mouser 1 watt LEDs range from 140 ma to 400 ma, so voltage must be from 2.5V to 7.14V.
Let's assume 140 ma and 2.5V to make a very safe tester.
7.4V - 2.5V = 4.9V
4.9V/.14A = 35 ohms.
Use 39 ohms, 3 watts to start the LED.
That will give an estimate of its proper voltage and we can work at this, bit by bit.
Why you told 39 ohms and 3 watts. What is 3 watts?
 

#12

Joined Nov 30, 2010
18,224
3 watts is the size of the resistor.
See post #14 and use 4 watt resistor.
Probably you can only buy 15 ohm resistor.
For 15 ohms, 3 watt resistor will be sufficient.
 

Thread Starter

imraneesa

Joined Dec 18, 2014
227
Mouser 1 watt LEDs range from 140 ma to 400 ma, so voltage must be from 2.5V to 7.14V.
Let's assume 140 ma and 2.5V to make a very safe tester.
7.4V - 2.5V = 4.9V
4.9V/.14A = 35 ohms.
Use 39 ohms, 3 watts to start the LED.
That will give an estimate of its proper voltage and we can work at this, bit by bit.
Why you said 2.5v as safe while 7.4v is high. Making tester for high volt is safe right. Also why you substract 2.5 from 7.4.
 

#12

Joined Nov 30, 2010
18,224
Why you still reading post #10 "How to find resistor with no information except 1 watt" when answer is in post #16? "How to find resistor after you tell us the current".

At this time, I do not have the patience required to type out how to use experimental data to do a decreasing boundary search based on some internet obtained information that might or might not be correct. The fact that I can do the search and find your resistor size is why I answered your question. If you want to know HOW to do the search, that is a different question.
Perhaps that question needs a new thread. The title might be, "How to find resistor for 1 watt LED with no other information provided".
 
Last edited:

blocco a spirale

Joined Jun 18, 2008
1,546
What is it with people and driving LEDs? Why do they make it so difficult? These LED threads go round and round and round.......

There was a time before the internet when we had no one to bother and instead we would pick up a pen and paper and a calculator and work it out for ourselves. And then we'd wire up some components and check our results. It's just basic electronics, right?

I guess nobody does that any more because it's easier just to make it someone else's problem and avoid the inconvenience of actually bothering to understand anything .
 

WBahn

Joined Mar 31, 2012
30,062
I want to check the driver for current. But I don't want to use LED before it spoil. I want to use some kind of test load so that I can use it and adjust the desired current and then finally will use led. Give me a calculation how to make test load for 1w LED. And if it is 500mW LED what will be the test load.
What kind of driver do you have? Is it a current source or is it a voltage source or is it something else?

You want your test load to develop the same voltage across it when it is dissipating 1W as the LED will have across it, so you need to know what the forward voltage drop of the LED is. If this is a single LED then if you know the color you can make a pretty reasonable guess about the voltage. If it is an array of LEDs, then all bets are off.

To find the forward voltage you can use a simple circuit that will get a small amount of current flowing and then measure the voltage across the LED. For instance, if you take a 9V battery and use a 1kΩ resistor then the most current that will flow when all of them are put in series will be 9mA and the power drawn from the battery will only be 81mW. That should be enough current to get you a reasonable voltage measurement of the LED forward voltage drop since it will not change by much as you increase the current.

So let's say that you do this and you measure a voltage of 3.7V across the LED. That means that when it is dissipating 1W of power that it will have about 3.7V across it (it will actually have a bit more, but not a lot since the voltage will increase by about 100mV or so for every factor of ten increase in current).

So now you want a resistor that will consume 1W with 3.7V across it, which since P=V²/R, means that you want R=13.7Ω and that your current will be about 270mA. Be sure that you use a resistor that is rated for at least 1W (a minimum rating of 2W is better).
 
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