Hi All,
Hypothetically, I have a resistor that will get very hot. It is underneath a block of thermally conductive resin , 1 mm thick, 10 cm x 10 cm area which is intended to dissipate the heat. The resin / compound has a maximum exposure temperature of 200°C, and thermal conductivity of 1.3 w/m.k. I also know the ambient temperature could reach +40°C. If I calculated the power dissipated by the resistor is it possible to calculate the temperature of the component without knowing it's thermal resistance? The idea is that I want to make sure the heat sinking is sufficient enough so that the resin does not burn.
To answer this I rearranged the heat transfer equation to give Temperature on the hot side, I have attached my excel calculations. Is this method OK to determine the temperature? My calcs suggest the resistor would need to dissipate 2kW to exceed 200°C, and at 100W it would only rise the temperature by about 7K
Hypothetically, I have a resistor that will get very hot. It is underneath a block of thermally conductive resin , 1 mm thick, 10 cm x 10 cm area which is intended to dissipate the heat. The resin / compound has a maximum exposure temperature of 200°C, and thermal conductivity of 1.3 w/m.k. I also know the ambient temperature could reach +40°C. If I calculated the power dissipated by the resistor is it possible to calculate the temperature of the component without knowing it's thermal resistance? The idea is that I want to make sure the heat sinking is sufficient enough so that the resin does not burn.
To answer this I rearranged the heat transfer equation to give Temperature on the hot side, I have attached my excel calculations. Is this method OK to determine the temperature? My calcs suggest the resistor would need to dissipate 2kW to exceed 200°C, and at 100W it would only rise the temperature by about 7K
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