So using the Hi-Tech ANSI C Compiler with MPLab.

Im getting this error message while compiling my code

symbol "u687" defined more than once

I've searched all around, and cannot find any useful information as to what is the cause of this.

If anyone has any knowledge of what this means, I would be very appreciative.

Thanks,
S

 

And where's the code? Does it contain u687 text or not?

 

My code has no reference to anything to do with "u687"...

This is why im so confused, I have no idea what it is..

 

So it appears its something to do with my interrupts

When i comment out my interrupt routine it compiles, however when i have my interrupt defined it doesnt work.

static void interrupt isr(void)
{
 disable_interrupts(); //Stop interrupts from interrupting the interrupt
 count = 25;
  while(count>0)   
  {
      PORTB = (PORTB | 0x90);    //Rotate stepper y direction 25 times
      delay(1000);
      PORTB = (PORTB | 0xC0);
      delay(1000);
      PORTB = (PORTB | 0x60);
      delay(1000);
      PORTB = (PORTB | 0x30);
      delay(1000);
      count--;
  }
 
 enable_interrupts();
}

This is with a PIC16F88..

Im guessing I am defining the interrupt routine wrongly ...
Does anyone know the correct method to define an interrupt in this situation?

 

So after a few long days of random testing, I finally found out that the error was because I can't call the delay function while in the interrupt.

Im not sure if this is normal or not, but its the only way it works.

 

It is a good practice not to call delay in ISR. ISR has to finish as soon as possible for many reasons. Another method to achieve what you are trying to do is to set a flag in ISR and have a loop outside the ISR checks that flag and do the required processing if set then clear the flag again when finished.