I know that this is going to be a stupid question, but I don't want to burn my circuit out.
I want to replace one 500k pot with 2 pots one for fine one for course and a 200k pot, again with 2 pots one for fine one for course.
Here is the question. On the circuit board they have a 500k and a 200k so would the total ohms of the 2 pots have to equal the output of the single pot.
I.e. replacing a 500k with one 450k and a 50k= 500k
i.e. replacing a 200k with one 180k and a 20k = 200k
Here is the next question. which way do I connect the 2 pots.
replacing the 200k does the 180k go on the left and the 20k on the right? or viceversa?
Replacing the 500k does the 450 go on top and the 50k on the bottom or viceversa?
I want to replace one 500k pot with 2 pots one for fine one for course and a 200k pot, again with 2 pots one for fine one for course.
Here is the question. On the circuit board they have a 500k and a 200k so would the total ohms of the 2 pots have to equal the output of the single pot.
I.e. replacing a 500k with one 450k and a 50k= 500k
i.e. replacing a 200k with one 180k and a 20k = 200k
Here is the next question. which way do I connect the 2 pots.
replacing the 200k does the 180k go on the left and the 20k on the right? or viceversa?
Replacing the 500k does the 450 go on top and the 50k on the bottom or viceversa?