Aaaahhhh! I see where you are off the track.Originally posted by davidand@Jun 8 2005, 08:43 PM
-8.6V/15 Ω =0.57mA
10V-(0.57)(60 Ω )=9.49V
[post=8339]Quoted post[/post]
The value -8.6V is the correct voltage at the emitter but it is not the voltage that is being "dropped" across the 15 ohm emitter resistor.
The voltage you need to be using is the voltage that you would measure across the 15 ohm resistor if you used a voltmeter to measure the voltage. Recall that the current flowing in the resistor by Ohm's Law is V/R where V is the voltage across the resistor R.
hgmjr