I seem to be missing some value needed...

Load = 1.5K

Full-wave rectifier (It's a US book so) f = 120Hz assumed

Vout peak = 18V

1% ripple factor = 100%(r) .: r = 0.01

And

but I don't have either value yet.

Then

Now I can solve that for C but I don't have the ripple Vpp but I do know it has a peak Vout of 18V. So, can I assume from the 1% ripple that it would then be 1% of 18V? .: Vr pp = 18V/100 = 0.18Vpp ripple and the VDC out is 18V - 0.09V= 17.91VDCout.

then C = ?

HINT: the book answer key gives 556 uF and putting into the Vr pp equation gives me a 180uVr pp, hmmm...

Load = 1.5K

Full-wave rectifier (It's a US book so) f = 120Hz assumed

Vout peak = 18V

1% ripple factor = 100%(r) .: r = 0.01

And

but I don't have either value yet.

Then

Now I can solve that for C but I don't have the ripple Vpp but I do know it has a peak Vout of 18V. So, can I assume from the 1% ripple that it would then be 1% of 18V? .: Vr pp = 18V/100 = 0.18Vpp ripple and the VDC out is 18V - 0.09V= 17.91VDCout.

then C = ?

HINT: the book answer key gives 556 uF and putting into the Vr pp equation gives me a 180uVr pp, hmmm...

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