I have a circuit that is supposed to measure a battery. It takes the form of a simple text book diff amp made from op amps. The picture is attached. The 10v in the schematic represents the battery, the 20 volt represents a voltage bias of the battery.
My question is does the bias (20v shown) affect the output? My impression is that the answer is yes. My impression is that the input terminals on the pins can only handle a voltage that is between the positive and negative rails, of the opamp supply. I've simulated this on two different simulators now.
Circuit maker seems to be ok with changing the 20 volt to even 1200volts. That seems ludicrous. Websim, digikeys on-line simulator, gives me the results I expect.
I don't want to be a cherry picker here. Does the bias(shown as 20v) matter? About when can I expect things to become undefined? My impression is about 36 volts, since thats the supply multiplied by 3 and the circuit attenuates by 3.
My question is does the bias (20v shown) affect the output? My impression is that the answer is yes. My impression is that the input terminals on the pins can only handle a voltage that is between the positive and negative rails, of the opamp supply. I've simulated this on two different simulators now.
Circuit maker seems to be ok with changing the 20 volt to even 1200volts. That seems ludicrous. Websim, digikeys on-line simulator, gives me the results I expect.
I don't want to be a cherry picker here. Does the bias(shown as 20v) matter? About when can I expect things to become undefined? My impression is about 36 volts, since thats the supply multiplied by 3 and the circuit attenuates by 3.
Attachments
-
25.1 KB Views: 28