I'm having trouble figuring out wich resistors are in paralell and wich are in series, can anybody help me? It was on a test in my university electronics class.

I have tried redrawing the circuit, but i get wrong answers, my teachers are on vacation so i thought i would try here!

 

Does this re-draw help?



John

 

Thanks John i think it does!

(100+220)//(600//400+220//400)

Total impedance aproximately 174,1Ω

Is that correct or did i mess it up?

 

{(400 || 600) + (400 || 220)} || (100 + 220)

Ramesh

 

I think that is what i did...

Got Total impedance aproximately 174,1Ω

 

174.1 Ω is what I got too.

Please let us know how you do on the rest of the questions.

John

 

I'm having some trouble (my brain is in vacation mode)...

In a paralell circuit the voltage is the same, so on my first try i got 32V on V1,V2 and Va, but this is sereis paralell and i'm not sure what to do, i'm reading about current dividers and voltage diveders now... All tips are apreciated!

 

Can the voltage be more than 32V? I tried voltage diveder formula for V1, V1=(600/174.1)*32V and got 110.3V

????????
Steinar

 

Can the voltage be more than 32V?

Not in that circuit.

I tried voltage diveder formula for V1, V1=(600/174.1)*32V and got 110.3V
????????
Steinar

174.1 is the total resistance seen by the battery. Calculate the total current. Then calculate how that current is proportioned between the two main parallel legs (redrawn below):


Now, you can calculate the voltages across the 400 and 600 Ω resistors using their paralleled resistance.

John

 

Ok, you are much better than my textbook... ;-p

I got 20.1 V for V1, but is it then the same for Va?

Feel kind of stupid right now....

 

Wouldn't Va referenced to ground be (32 - V1)? You can double check that with the current you calculated and the paralleled resistance of the 220 Ω and 400 Ω resistors.

John