Hi !
I have a Panasonic NCR18650B Li-ion battery. The datasheet is here: https://www.tme.eu/Document/3e0170a1e089819f286f7066e69035b4/NCR18650B.pdf
In my circuit, the battery is monitored with a microcontroler and I know the voltage, current, temperature, internal resistance (70-100mR @ 25*C). What I want is to determine roughly when the battery state of charge has dropped bellow a certain point (lets say 30%). From the first graph in the datasheet it seems that the 30% is at around 3.5V with no load and 25*C. Now, when connecting a load, the voltage drops due to internal resistance and I can calculate it. It follows the values in the discharging graph with multiple loads. But the thing is that the internal resistance varies with temperature, and I want my estimation to be as correct as possible. The second graph shows the cell voltage when discharging with 3.2A at various temperatures. I don't really know what should I understand from here... At 30% (2500mAh capacity) and 0*C it seems that the voltage drops with another 0.2V. So, 30% will be 3.5V - 0.3V (3.2A load drop) - 0.2 (temperature drop) = 3.0V. Is this correct ? Ok, but then, how do I know how much voltage will drop due to temperature for other load currents ? Will it be proportional ? 0.2V / 3.2A = 63mV/A additional drop @ 0*C ?
I have a Panasonic NCR18650B Li-ion battery. The datasheet is here: https://www.tme.eu/Document/3e0170a1e089819f286f7066e69035b4/NCR18650B.pdf
In my circuit, the battery is monitored with a microcontroler and I know the voltage, current, temperature, internal resistance (70-100mR @ 25*C). What I want is to determine roughly when the battery state of charge has dropped bellow a certain point (lets say 30%). From the first graph in the datasheet it seems that the 30% is at around 3.5V with no load and 25*C. Now, when connecting a load, the voltage drops due to internal resistance and I can calculate it. It follows the values in the discharging graph with multiple loads. But the thing is that the internal resistance varies with temperature, and I want my estimation to be as correct as possible. The second graph shows the cell voltage when discharging with 3.2A at various temperatures. I don't really know what should I understand from here... At 30% (2500mAh capacity) and 0*C it seems that the voltage drops with another 0.2V. So, 30% will be 3.5V - 0.3V (3.2A load drop) - 0.2 (temperature drop) = 3.0V. Is this correct ? Ok, but then, how do I know how much voltage will drop due to temperature for other load currents ? Will it be proportional ? 0.2V / 3.2A = 63mV/A additional drop @ 0*C ?

