The horizontal line should be the Common Ground for the Input Voltage and Output Voltage.sorry, i meant why isn't the arrow connected to the horizontal line?
I'm sorry. I just cannot see the diagram the way you are seeing. It's my fault that I perceive the answer to your question is so obvious. You ask. "...why isn't the arrow connected to the horizontal line?" And all I can come up with is, "Because it isn't!"sorry, i meant why isn't the arrow connected to the horizontal line?
Hi, check for open circuit, it may look un likely but it's the only reason to your questionsi need to determine the voltage ranges for voltage divider circuits that contain rheostats. here are what i got for each circuit (i've just learned about these so please correct me if i'm wrong)
this is the first circuit. here's what i think
1) if R2 = 0 ⇒ Vout = Vin / R1
2) if R2 = R2max ⇒ Vout = Vin / (R1 + R2)
View attachment 120929
this is the second circuit and my results
1) if R1 = 0 ⇒ Vout = Vin / R2
2) if R1 = R1max ⇒ Vout = Vin / (R1 + R2)
View attachment 120931
for the last circuit i need to prove why is the range 0-Vin
1) R1 = 0 ⇒ Vin and Vout are connected so Vout = 0
2) R1 = R1max ⇒ (i can't prove this, i don't think it is Vout = Vin / R1)
View attachment 120932
any help would be appreciated. thanks
The one with common gndYes @ScottWang, I agree. I was making that assumption that the horizontal green line was ground. This graphic illustrates what I was assuming. It's similar to yours and differs only in that it uses the red dot as a junction, similar to the TS diagrams where the "rheostat" connections are made.
View attachment 120956
Basically, the question comes down to how accurate the original drawings were? Which one below is correct?
View attachment 120957
okay i'll take it as it isAnd all I can come up with is, "Because it isn't!"