Hi,
I have problem doing this problem:
It is the problem #5 on the attachment.( I was not able to remove problem#4)

Please can you give me some guidance?
I know that for t>0( steady state) the inductor is like a short and the capacitor like an open circuit.

Do I need to replace the inductor by a short and cancel the part with the capacitor and then do a KVL and solve for V(t)?

Thank you
B

 

tell me is t>o a time between 0 and infinity (i;e where the circuits functions properly or is it the moment just after the closure of the switch (i have not kept touch with this for a long time now)
since u mention steady state probably the first assumption is correct.
IIRC in that case u should not open or short anything just solve with initial conditions which should be voltage across capacitor.

 

I think it is the 0 to infinity.
However, I was wondering if I need to study the case just before the switch closes.

Still vague.
B

 

yes the initial condition of the circuit comes into effect.
b4 closure there wud have been some voltage across cap u will need to take this into consideration.
but u dont need to modify the crkt (no short and open reqd-the components remain as they are)
u only need to write the v(T) using KVL for this circuit.