I have taken a look at several websites for regenerative receivers including the one below from http://www.electronics-tutorials.com/receivers/regen-radio-receiver.htm:
They all seem to have one thing in common. the coupling resistor is at least double of the quench frequency resistor. In this circuit, the quench resistor (R3) is 2.7K and the coupling resistor is 5.6K (R4).
Now I tried ratios myself. I tried making R3 and R4 in my circuit equal values, and that did not seem to work well. (the stations I picked up were replaced with noise). I also tried 15K for R3 and 36K for R4, and it worked better. (I can receive stations, but some are not coming in clearly).
Does anyone know the mathematics behind R3 and R4, or can someone explain to my why R4 must be double of R3 (instead of 1 1/2 times, or 3 times)?
thanks.
They all seem to have one thing in common. the coupling resistor is at least double of the quench frequency resistor. In this circuit, the quench resistor (R3) is 2.7K and the coupling resistor is 5.6K (R4).
Now I tried ratios myself. I tried making R3 and R4 in my circuit equal values, and that did not seem to work well. (the stations I picked up were replaced with noise). I also tried 15K for R3 and 36K for R4, and it worked better. (I can receive stations, but some are not coming in clearly).
Does anyone know the mathematics behind R3 and R4, or can someone explain to my why R4 must be double of R3 (instead of 1 1/2 times, or 3 times)?
thanks.