# Resistence seen by a capacitator,how to solve them?

Thread Starter

#### huking1000

Joined Jan 1, 2016
2
Are e any texts e who explain how to find the resistence seen by a capacitator,and when there are other capacitators on the circuit,to know if they are indipendent or not

#### Dodgydave

Joined Jun 22, 2012
9,956

#### anhnha

Joined Apr 19, 2012
881
Are e any texts e who explain how to find the resistence seen by a capacitator,and when there are other capacitators on the circuit,to know if they are indipendent or not
What do you mean with "resistance seen by a capacitor"?

Thread Starter

#### huking1000

Joined Jan 1, 2016
2
fors example find the resistance seen by Cd,with the generator V1 turned off ,and let's put a generator Va in Cd and let's measuce the current at its terminals and see if the other capacitor C influences or not the resistance seen by Cd,I mean if we consider C open does it influence the resistance,what if we consider it closed

#### Narcis992

Joined Jan 1, 2016
2
resistor R1 parallel with a condensator C1 how can i find that the resistence or the condensator its a bad component?
How can i measure it?
for example :R1=1kohm C1=1uF after i've measured R1 with multimeter it has 700 ohm (C1 its bad or R1 its bad?Without to remove the resistence?)

#### anhnha

Joined Apr 19, 2012
881
fors example find the resistance seen by Cd,with the generator V1 turned off ,and let's put a generator Va in Cd and let's measuce the current at its terminals and see if the other capacitor C influences or not the resistance seen by Cd,I mean if we consider C open does it influence the resistance,what if we consider it closed
As I see when V1 is turned off, two voltage-controlled current sources are zero. So impedance seen by CD will be Z = RD1 + R|| 1/(sC) + RD2 and the resistance is the real part of Z. It depends on C.

#### Jony130

Joined Feb 17, 2009
5,230
• anhnha

#### Narcis992

Joined Jan 1, 2016
2
As I see when V1 is turned off, two voltage-controlled current sources are zero. So impedance seen by CD will be Z = RD1 + R|| 1/(sC) + RD2 and the resistance is the real part of Z. It depends on C.
So in a PCB after multimeter measurements R1 or C1 which one of them are destroyed or something like that?

Similar threads