I have been given the following practice exam question, and am struggling to figure it out. Could someone break it down for me and explain how to work out the following:
A d.c. self-excited shunt generator has a field resistance of 160Ω. The generated emf is 420V and it supplies a load of 55kW. Calculate the armature resistance when the generator terminal voltage is 408V.
Thanks
A d.c. self-excited shunt generator has a field resistance of 160Ω. The generated emf is 420V and it supplies a load of 55kW. Calculate the armature resistance when the generator terminal voltage is 408V.
Thanks