It's probably a reasonable assumption that the DC resistance of L2 is << R6, which is 20 kΩ.You don't know the DC resistance of the inductor L2, so you can't find it.
C2 isolates L1 in DC steady state, but not L2.C2 isolates the inductor so the steady state current is zero around this bit.
Frank
So R1 and R2 don't factor into it at all?If its a short circuit, it will form a voltage divider with the resistors R4,6 so it will be half of the supply voltage, which is 160V.
Power is measured in Watt. Why is your result in volts?Thankyou good people Also on the same question how do I work out the power dissipation, Ive worked it out and got 512mV but don't know if its correct. Thanks
by Luke James
by Luke James
by Luke James