I was asked to measure the frequency response of the simple RC low pass filter but am not sure if i have done this right or not ? if you could tell me that would be great .

So I've done
1
1+2*3.14*100*0.02*1000

Voltage source 10V
100Hz then have to do 100kHz
C=0.02

and i was also told to and record the attenuation at 15 to 20 frequencies logarithmically spaced over this frequency range. but i have no clue how to do that .

 

Hello there
Welcome to AAC!
Pardon me for asking but is this homework?
My crystal ball is buffering right now

 

Hello there
Welcome to AAC!
Pardon me for asking but is this homework?

No am just trying to revising for my exam , and found a pdf about Frequency response network and was trying to complete it, and now am stuck on Q3 and not sure how to do it now .

 

Excellent answer I believe you but I believe everybody stand by please

 

Here is a plot of a 1 Farad Capacitor being charged through a 1 Ohm Resistor. The logarithmic scale on the vertical axis shows that the voltage on the capacitor a low frequencies is equal to the voltage source. The logarithm of Vc/Vin =1 and the logarithm of 1 is 0, thus 0 dB. The green curve is computed by taking 20*log(Vc/Vin).

 

That formula is so close it hurts!

I would suggest having a quick google of "RC low pass circuit" and find a tutorial and you'll see how close you were