Can you show the circuit you want to analyze? It is best to see the circuit when talking about these details.Yes it is very efective to find the transfer function with the impedance. My problem is that when i take the the diagram of the discharging equation(differential equation) i get exp(-x/RC) graph everything is ok here, but when i try to get the free response of this system with the transfer function i get the opposite of this function exp(x). Is this right?
You need to show the problem you are trying to solve and your best attempt to work it. Otherwise we have very little to go on and are highly likely to end up talking at cross purposes because our crystal balls didn't show us your circuit as we were guessing.Yes it is very efective to find the transfer function with the impedance. My problem is that when i take the the diagram of the discharging equation(differential equation) i get exp(-x/RC) graph everything is ok here, but when i try to get the free response of this system with the transfer function i get the opposite of this function exp(x). Is this right?
@Saitron, yes that is what you get e^-at and then you have to solve for the constant using the initial conditions. You then get the full result you are probably expecting. So there are really two steps involved. One to solve the DE as you have done and then another to apply the initial conditions.Yes it is very efective to find the transfer function with the impedance. My problem is that when i take the the diagram of the discharging equation(differential equation) i get exp(-x/RC) graph everything is ok here, but when i try to get the free response of this system with the transfer function i get the opposite of this function exp(x). Is this right?
Well the exponent is always negative for this.Hahaha don't troll me dudes.. i guess i would be more helpful if i show you the circuit. Ok let's go to the topic. I have this circuit and i charge it with 100V, R=1, C=3F, then i disconect the source and let the capacitor discarge. I know that the function on the capacitor is V=Voe^(-t/RC) and i can get the graph. My problem is how to get the transfer function of this because the graph of the differential funtion is kind of exp(-x) and the graph of the transfer function is exp(x). Is it this rightView attachment 203128
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by Jake Hertz
by Jake Hertz
by Jake Hertz