AWG 10 is 1.02ohm per 1000ft 500ft x 2 conductor is 1000ftPlease show your work.
12.5A is I squared to calculate the power dropWhy are you using 12.5A in the second calculation?
Perhaps you should try to figure out the equivalent series resistance of the circuit and apply Ohm's law to that.
Being homework I tried to hint at this, above, rather than simply say it.You need to include the resistance of the wire to determine the heater current as it will draw less than its rated power due to the wire resistance..
And I think the question is asking for the power lost in the wire resistance.
Yes as others have pointed out, unless you are trying to keep it extremely simple you need to calculate the voltage drop too in order to determine the correct current draw.AWG 10 is 1.02ohm per 1000ft 500ft x 2 conductor is 1000ft
C=p/v 1500W/120V=12.5A
p=I*x R 12.5* x 1.02ohms = 159.37W
1500w - 159.37 = 1340.63W is the correct???