yes sir.hi yaron,
Is this a College assignment.?
E
Why do you think it would?Does this reference voltage (vcc/2) effects the value of beta ?
Hello,Hello everyone!
I would like to know, Does this reference voltage (vcc/2) effects the value of beta ?
beta = (ve/vo while vin=0)
thank you !
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I am guessing that this is a highly theoretical question where practical things like that are often left out.Your opamp is missing a very important resistor:
The definition of beta is not clear. What is Ve and what is Vo? And what is ε ?Hello everyone!
I would like to know, Does this reference voltage (vcc/2) effects the value of beta ?
beta = (ve/vo while vin=0)
thank you !
View attachment 271278 View attachment 271280
Hi,Maybe ve translates to "V input" and beta translates to "gain"?
Isn't the differentiator a highpass filter?
Yes - that`s correct.Hi,
Strictly speaking, the transfer function for an ideal differentiator is:
s*R*C
Hi,Yes - that`s correct.
But it is to be noted that in reality this circuit (without the stabilizing resistor) will not work.
Due to the real opamp gain function the circuit will oscillate.