yes sir.hi yaron,
Is this a College assignment.?
E
Why do you think it would?Does this reference voltage (vcc/2) effects the value of beta ?
Hello,Hello everyone!
I would like to know, Does this reference voltage (vcc/2) effects the value of beta ?
beta = (ve/vo while vin=0)
thank you !
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I am guessing that this is a highly theoretical question where practical things like that are often left out.Your opamp is missing a very important resistor:
The definition of beta is not clear. What is Ve and what is Vo? And what is ε ?Hello everyone!
I would like to know, Does this reference voltage (vcc/2) effects the value of beta ?
beta = (ve/vo while vin=0)
thank you !
View attachment 271278 View attachment 271280
Hi,Maybe ve translates to "V input" and beta translates to "gain"?
Isn't the differentiator a highpass filter?
Yes - that`s correct.Hi,
Strictly speaking, the transfer function for an ideal differentiator is:
s*R*C
Hi,Yes - that`s correct.
But it is to be noted that in reality this circuit (without the stabilizing resistor) will not work.
Due to the real opamp gain function the circuit will oscillate.
by Jake Hertz
by Jake Hertz
by Duane Benson